Question

please help

Answer 1

@AaronAndyson

Answer 2

So we have a point \(\large P\) which is going to be subject to a translation according to the rule \(\large (x + 3, y-1)\) to arrive at a new point \(\large P'\)

So what we do, is take our coordinate of point \(\large P\) and apply the translation

\[\large P = (-5,2)\]
Since the translation is \(\large (x+3,y-1)\) we simple add 3 to our 'x' coordinate...and subtract 1 from our y-coordinate

\[\large P' = P(x + 3,y-1) \rightarrow (-5 + 3, 2 - 1) \rightarrow (-2,1)\]

So our new point \(\large P'\) is \(\large -2,1\) after the translation is applied