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Mathematics 8 Online
OpenStudy (ageta):

Acceleration Stuff :)

OpenStudy (ageta):

someone help me with how i can find acceleration due to gravity

OpenStudy (welshfella):

You can get an approximate value by dropping an object from a building of known height and measuring the time it takes to hit the ground

OpenStudy (ageta):

ok i know the time and the height can we do an example

OpenStudy (ageta):

T=1.01 H=7.57m

OpenStudy (welshfella):

use one of the equations of motion for uniform acceleration s = (1/2)a t^2 where s = height , t = time and a = acceleration due to gravity so we have 7.57 = (1/2)a (1.01)^2 solve for a.

OpenStudy (ageta):

i thought a is 9.8

OpenStudy (welshfella):

yes it is

OpenStudy (ageta):

oh i get it

OpenStudy (ageta):

on earth it is 9.8

OpenStudy (welshfella):

9.8 ms-2

OpenStudy (welshfella):

right - on another planet it could be different.

OpenStudy (ageta):

mars LOl

OpenStudy (ageta):

do you know how to find percent error for best results

OpenStudy (welshfella):

hmm.. maybe . but Please post an other question separately

OpenStudy (ageta):

ok

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