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Mathematics 10 Online
OpenStudy (lowkey.s):

HELP @kevin

OpenStudy (lowkey.s):

OpenStudy (lowkey.s):

@qwertty123

OpenStudy (kevin):

mean difference for high temperature : ( 10 + (-1) + 2 + (-3) + (-1) + (-1) ) / 6 = 1 mean difference for low temperature : ( (-2) + 0 + 1 + (-1) + (-1) + 1 ) / 6 = -1/3 -1/3 --> it's between -1 and 0

OpenStudy (kevin):

Hope this one is correct :)

OpenStudy (kevin):

I calculate it by myself. You can check it again

OpenStudy (lowkey.s):

for the first question right?

OpenStudy (kevin):

It's the answer for first and second question

OpenStudy (lowkey.s):

i calculate its right.

OpenStudy (lowkey.s):

Oh no wonder why I got confused for a sec...

OpenStudy (kevin):

lol

OpenStudy (kevin):

Pls check it again

OpenStudy (lowkey.s):

the mean difference for the first question whats the integer? or is it between two integers?

OpenStudy (lowkey.s):

I menat the mean difference for high temp.

OpenStudy (kevin):

You can rewrite it using your own language. It should be like this when you rewrite it : the mean change in the forecasted high temperatures over the next 7 days (for mean difference for high temperature) AND the mean change in the forecasted low temperatures over the next 7 days (for mean difference for low temperature)

OpenStudy (lowkey.s):

you know the "mean" doesnt meant "mean, median, quartile, and range. rights?

OpenStudy (kevin):

For mean difference for high temperature is already integer, so you don't need to write what integers is between

OpenStudy (kevin):

I know it all

OpenStudy (lowkey.s):

OH lol!! I SEE hahaa okay. im srry i really dislike math

OpenStudy (kevin):

XD

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