HELP @kevin
@qwertty123
mean difference for high temperature : ( 10 + (-1) + 2 + (-3) + (-1) + (-1) ) / 6 = 1 mean difference for low temperature : ( (-2) + 0 + 1 + (-1) + (-1) + 1 ) / 6 = -1/3 -1/3 --> it's between -1 and 0
Hope this one is correct :)
I calculate it by myself. You can check it again
for the first question right?
It's the answer for first and second question
i calculate its right.
Oh no wonder why I got confused for a sec...
lol
Pls check it again
the mean difference for the first question whats the integer? or is it between two integers?
I menat the mean difference for high temp.
You can rewrite it using your own language. It should be like this when you rewrite it : the mean change in the forecasted high temperatures over the next 7 days (for mean difference for high temperature) AND the mean change in the forecasted low temperatures over the next 7 days (for mean difference for low temperature)
you know the "mean" doesnt meant "mean, median, quartile, and range. rights?
For mean difference for high temperature is already integer, so you don't need to write what integers is between
I know it all
OH lol!! I SEE hahaa okay. im srry i really dislike math
XD
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