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Two cyclists, 96 miles apart, start riding toward each other at the same time. One cycles 2 times as fast as the other. If they meet 4 hours later, what is the speed (in mi/h) of the faster cyclist? a. Write an equation using the information as it is given above that can be solved to answer this problem. Use the variable r to represent the speed of the slower cyclist. b. What is the speed of the faster cyclist?
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@satellite73
One travels speed r, the other is 2*r, overall the distance is being covered at r+2r = 3r, the sum of their speeds.
Distance = rate*time 96 = 3*v*4
so thats the equation
yes, d = ( r + 2r)*t 96 = (r + 2r) * 4 96 = 12r r=8 mi/h
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okay thanks
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