Suppose scores on a standardized test taken by future doctors are normally distributed w/ a mean of 10.5 and a standard deviation of 2.2.... ...Approximately 70% of the future doctors scored less than what score? The teacher says that the answer is 11.6 and honestly, I don t see why? Please explain with work shown towards why it is 11.6? B/c I have tried so many times messing with the standardizing data formula and I cannot seem to figure it out...I don t know what I am doing wrong....Please help?
@Helpmeeasetjx @helpkay
The first step is to use a normal distribution table to find the z-score that corresponds to a cumulative probability of 0.7. The z-score for a cumulative probability of 0.7 is 0.525. Now we can write: \[\large 0.525=\frac{X-10.5}{2.2}\] Next you just need to solve to find the value of X.
All right thanks @kropot72
You're welcome :)
@kropot72 u think u can help me with another problem?
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