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help with rational expressions (college alg)
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\[\frac{ \frac{ 1 }{ x }-\frac{ 1 }{ y } }{ x^2-y^2 }\]
factor the denominator you know how to do that?
no... (xy)(x-y)???
\[x^2-y^2=(x+y)(x-y)\]
also do the subtraction in the numerator
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i.e. compute \[\frac{1}{x}-\frac{1}{y}\]
\[\frac{ 1y-1x }{ xy }\]
right
although i would not put the 1's there, your teacher will think you are daft
so you got \[\frac{\frac{y-x}{xy}}{(x+y)(x-y)}\]
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put the denominator in the deominator where it belongs, get \[\frac{y-x}{xy(x+y)(x-y)}\] then you can cancel
2y?
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