Question

Help me out.. I will medal!

Answer 1

@mathmale @danieldjpon3 @beckyg @NvidiaIntely @Will.H

Answer 2

ugh brb im kinda busy

Answer 3

Sorry, I have no idea how to do this :(

Answer 4

Its okay, thanks for taking a look anyways.

Answer 5

If you know anyone who is good with this stuff please tag them lol

Answer 6

Are you new here?
Let me know if you need help :)

Answer 7

Oh okay, I will try and get someone :)

Answer 8

Yes I am new :) thank you

Answer 9

@iGreen @TheSmartOne @Nnesha @Conqueror @cuanchi @Helpz-Q @kittiwitti1 @shaima @Unavailabilityy @Will.H

Answer 10

._.

@NvidiaIntely I don't have time to help in other subjects... e_e

Answer 11

Okay fine.

Answer 12

@sissyedgar @glitter

Answer 13

@jabez177

Answer 14

@kevin99m @Kevin

Answer 15

Do you mean like this ?
f(x) = sqrt(x-2)
g(x) = sqrt(x+7)
(f o g) x = ....

Answer 16

@rosepetalingg

Answer 17

pretend like there is a space between the 2 and the g lol

Answer 18

\[(f \times g) x = f(x) \times g(x)\]
get it?

Answer 19

so what is the first step here?

Answer 20

do i plug in the equtions.. do I find the domain

Answer 21

assume the domain is
x = {x | x E R}

Answer 22

what you need is to find the range now

Answer 23

f(x)=sqrt(x−2)
g(x)=sqrt(x+7)

So (f x g)(x) would be ?

Answer 24

wouldnt the range be 0, infinity

Answer 25

wait no lol

Answer 26

ok is it square root(x^2+5x-14) ?

Answer 27

Ok, I will give you further information

\[(f \times g)(x)\]\[ = f(x)\times g(x)\]
\[=\sqrt{x-2} \times \sqrt{x + 7}\]

Answer 28

soo x^2+5x-14

Answer 29

Now simplify the equation I gave you above

Answer 30

Thank you for your help!!

Answer 31

wait.. do i leave the square root on my final answer or take it off? @kevin

Answer 32

It cannot be simplified furthermore. The final answer would be still in square root

Answer 33

ok thanks so much!! :)

Answer 34

yw :)