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OpenStudy (katecc379):
OpenStudy (katecc379):
@jim_thompson5910
jimthompson5910 (jim_thompson5910):
Recall that \[\Large (f \circ g)(x) = f(g(x))\]
OpenStudy (katecc379):
yes i know how to do that
jimthompson5910 (jim_thompson5910):
Start with f(x). Replace every x with g(x).
\[\Large f(x) = \sqrt[3]{x+2}\]
\[\Large f({\color{red}{x}}) = \sqrt[3]{{\color{red}{x}}+2}\]
\[\Large f({\color{red}{g(x)}}) = \sqrt[3]{{\color{red}{g(x)}}+2}\]
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jimthompson5910 (jim_thompson5910):
so we end up with `g(x)+2` and we want that to be equal to `x+3`
so set the two expressions equal to one another and isolate g(x)
jimthompson5910 (jim_thompson5910):
g(x) + 2 = x+3
g(x) = ????
OpenStudy (katecc379):
x+1?
jimthompson5910 (jim_thompson5910):
yep
OpenStudy (katecc379):
ok can u help with one more?
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jimthompson5910 (jim_thompson5910):
sure
OpenStudy (katecc379):
howve you been its been forever haha
OpenStudy (katecc379):
jimthompson5910 (jim_thompson5910):
I'm doing well. How about you?
jimthompson5910 (jim_thompson5910):
the same idea will apply here
but now we have 3 functions this time
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OpenStudy (katecc379):
pretty good busy i work 12 hours everyday and take 7 classes online so im pretty stressed
jimthompson5910 (jim_thompson5910):
the inner most function is h(x)
replace every x in h(x) with 4. Then evaluate to get what?
OpenStudy (katecc379):
sq rt of 4?
OpenStudy (katecc379):
2?
jimthompson5910 (jim_thompson5910):
`i work 12 hours everyday and take 7 classes online`
that sounds like an impossible task, but somehow you're making it work
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jimthompson5910 (jim_thompson5910):
yes the square root of 4 is 2
jimthompson5910 (jim_thompson5910):
now you'll plug that into g(x)
OpenStudy (katecc379):
yeah somehow couldnt tell you how haha but 7?
jimthompson5910 (jim_thompson5910):
plug x = 2 into g(x) to get ???
jimthompson5910 (jim_thompson5910):
yep 7
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OpenStudy (katecc379):
okay then what
jimthompson5910 (jim_thompson5910):
then that result is fed into f(x)
jimthompson5910 (jim_thompson5910):
it's like a chain reaction
OpenStudy (katecc379):
so 28
jimthompson5910 (jim_thompson5910):
yep
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