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Algebra 13 Online
OpenStudy (marceljr59):

Solve for x: −2x − 4 > 8 a x < −6 b x > −6 c x < −2 d x > −2

Awolflover1 (awolflover1):

\[−2x−4+4>8+4\]

Awolflover1 (awolflover1):

Add 4 to both sides^

Awolflover1 (awolflover1):

\[8+4=?\]

OpenStudy (marceljr59):

ok

OpenStudy (marceljr59):

12

Awolflover1 (awolflover1):

\[−2x>12\] Divide both sides by -2

OpenStudy (marceljr59):

-6

OpenStudy (marceljr59):

so b

Awolflover1 (awolflover1):

yes correct ^_^

OpenStudy (marceljr59):

I gave you a medal

jhonyy9 (jhonyy9):

@Awolflover1 sorry for my intervention but when you divide by a negativ number dont necessary changing the sign > inversed < so than i remember it right ? @TheSmartOne ? please

TheSmartOne (thesmartone):

Yes, you have to change the sign when you divide/multiply an inequality by a negative number Eg. -4x > 4 Divide -4 on both sides and change sign x < -1

jhonyy9 (jhonyy9):

so x < -6 is the right answer

jhonyy9 (jhonyy9):

so this mean that choice a. is the right answer and not b.

jhonyy9 (jhonyy9):

TSO am i right please ?

jhonyy9 (jhonyy9):

−2x − 4 > 8 not b. so choice a. is the right answer bc. x<-6 so for example x = -7 -2(-7) -4 >8 14-4 > 8 10 >8 but for choice b. so x>-6 so for -5 -2*(-5) -4 > 8 10 -4 >8 6 not is greater than 8 - this is false @TheSmartOne sorry for your derange but an human calc.. with level 99 missing something in this way is accepted here on OS ? excuse me for this intervention and question

TheSmartOne (thesmartone):

yes it is allowed

jhonyy9 (jhonyy9):

ok, i will try understanding but the asker have got a false answer in this way now - ot not ?

jhonyy9 (jhonyy9):

sorry - and ty or your help good luck for today i go sleeping bc. here is in the night 2,39 oclock bye bye

TheSmartOne (thesmartone):

yes :)

TheSmartOne (thesmartone):

good night

Awolflover1 (awolflover1):

Hmm Oops! yes you're correct @jhonyy9 with > < i didn't check it :\ Thanks for correcting me @jhonyy9

Awolflover1 (awolflover1):

< >*

jhonyy9 (jhonyy9):

np yw

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