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\[\frac{ \sin^2\Theta }{\cos \Theta } \]
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@GIitter
@Speedsterpro i need help simplify that
Recall your basic Pythagorean Identity,\[\large\rm \sin^2\theta+\cos^2\theta=1\]Subtracting cosine squared gives us this,\[\large\rm \color{orangered}{\sin^2\theta=1-\cos^2\theta}\]Do you see how we can apply this identity to our problem?\[\large\rm \frac{\color{orangered}{\sin^2\theta}}{\cos \theta}=\quad ?\]
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no
Really? 0_o But but... I color-coded it :c lol
oh
\[\large\rm \frac{\color{orangered}{\sin^2\theta}}{\cos \theta}=\quad \frac{\color{orangered}{1-\cos^2\theta}}{\cos \theta}\]ya?
yea
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Then split it into two fractions,\[\large\rm =\frac{1}{\cos \theta}-\frac{\cos^2\theta}{\cos \theta}\]
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