Question

Help me please. I understand most of the concept but im still having difficulty.

x^2 - 9 =0

we're solving quadratics by completing the square using the square root property

Answer 1

Okay.
What is the square root of x^2?

Answer 2

And what is the square root of 9

Answer 3

would the square root of x^2 be x
and the square root of 9 be 3?

Answer 4

Indeed

Now form parentheses to gather the data that we have so far
(x 3) (x 3) = 0
What would be the sign in between those terms? Positive or negative for the 1st parentheses and positive or negative for the second?

Answer 5

Hint
In the original expression
X^2 - 9
We have a negative sign in between. That would lead to eliminate the term in the middle which would require both positive and negative signs.. Any ideas?

Answer 6

would it be + for the first set of parentheses and - for the second set?
such as (x+3)(x-3)

Answer 7

It would be.. For one of them
(x -3) (x+ 3) = 0
See that if we get to simplify this
We would get the following, after applying destrubtive property
x * x = x^2
X * 3 = 3x
-3 * x = -3x
-3 * 3 = -9
Which means
x^2 + 3x -3x -9 = 0
Notice that the terms in the middle
3x and -3x can be eliminated which would leave us with
x^2 -9 = 0
See that we got the same original expression which means our answer is right. That's one way to check your work

Answer 8

oh okay.