Rewrite the expression without using a negative exponent.
3v^−2
Simplify your answer as much as possible.
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OpenStudy (1davey29):
A negative exponent simply means to divide 1 by that term, so 3*v^-2 is the same as 3*(1/(v^2))=3/(v^2)
jhonyy9 (jhonyy9):
use formula a^-1 = 1/a
OpenStudy (motherhen544):
Can you put that in a picture because that looks really confusing
OpenStudy (motherhen544):
I just really don't get this concept at all
jhonyy9 (jhonyy9):
\[a^{-1}= 1/a\]
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jhonyy9 (jhonyy9):
ok. ?
OpenStudy (motherhen544):
Im still confused
OpenStudy (motherhen544):
like i said i just don't get it and I've never seen that formula before.
jhonyy9 (jhonyy9):
why ?
there is y^(-2) = ?
OpenStudy (1davey29):
It's not really a formula, more of a rule of exponents. The concept uses rules of dividing exponents (ex. x^2/x=x^(2-1)=x), as 1=x^0 so 1/x=x^0/x^1=x^(0-1)=x^-1. Same with -2. x^0/x^2=x^(0-2)=x^-2
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OpenStudy (motherhen544):
would it be 9v?
OpenStudy (motherhen544):
or no
OpenStudy (skullpatrol):
no
OpenStudy (motherhen544):
I don't get it at all
OpenStudy (1davey29):
The exponent only applies to the 3 if it's in parenthesis ((3v)^2). Otherwise, it just applies to the v.
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