Question

The equation below shows the relationship between the temperature in degrees Celsius, C, and degrees Fahrenheit, F:

C = 5 over 9(F − 32)

Which of the following formulas correctly solves for F?
F = 9 over 5C + 32
F = 9 over 5C − 32
F = 9C + 32 over 5
F = 9C − 32 over 5

Answer 1

@zepdrix

Answer 2

I'd suggest that you actually solve the given equation for F.
To eliminate fractions, mult. both sides of the given eq'n by 9. Show your results.

Answer 3

That's the part I'm having trouble with...

Answer 4

surely you can multiply that C by 9. Try it. Your result?

Answer 5

I stink at math :/ This I so confusing... :(

Answer 6

Such statement do not help you and do not help me. You have seen this math before and should have little or no trouble with it.

Answer 7

The given equation begins with C.
Multiply that by 9.

Answer 8

\[\frac{ 9 }{ 5 } \div C=?\]

Answer 9

I meant the multiply sign

Answer 10

I gave you C and asked that you multiply it by 9. Try again.

Answer 11

If I give you 5 and ask you to mult. that by 3, you'd write 3(5) = 15.
If I give you C and ask you to mult. that by 9, you'd write ... what?

Answer 12

3(C)

Answer 13

but wouldn't 9 times c be 9c? Why the 3?

Answer 14

Oh sorry I thought I put 9

Answer 15

C = (5 over 9)(F − 32)

You have mult. that C by 9 and gotten 9C. Now multiply that (5 over 9) by 9. Your result? (You have to keep that (F-32) as part of the resulting equation.)

Answer 16

Left side: 9C
Right side: 9(5/9)(F-32) Please simplify this.

Answer 17

Please simplify:\[9(\frac{ 5 }{ 9 })(F-32)\]

Answer 18

Would it be 5?

Answer 19

5C

Answer 20

The 9 cancels out, yes. That leaves you with 5(F-32). You cannot drop or forget the (F-32).

You began with C = 5 over 9(F − 32)

and now you have 9c=5(F-32).

Divide both sides by 5, so that you'll have (F-32) on the right side. please show your work.

Answer 21

Left side: divide 9C by 5. Type out your result.

Answer 22

I need your response, very soon, if y ou want me to continue here.

Answer 23

You would divide and it would become 6.4 right>?

Answer 24

Divide 9C by 5. All you have to do is retype this into one fraction.

Answer 25

Type 9C in the numerator of your fraction and 5 in the denom.

Answer 26

9/5C

Answer 27

9C/5 would be better.

Now divide 5(F-32) by 5.

Answer 28

6.4?

Answer 29

You have [ 5 times (F-32) ] and need to divide this whole expression by 5. Try again. Do NOT change or drop the (F-32) part.

Answer 30

What?

Answer 31

I can't type that any clearer than I already have. Think about this and then answer my question.

Answer 32

Simplify \[\frac{ 5(F-32) }{ 5 }\]

Answer 33

As I said before, leave the (F-32) part alone. Focus on the 5/5.

Your result?

Answer 34

Just the 5/5 which would cancel it out. You have F-32 keft?

Answer 35

yes.

Answer 36

so now you have\[\frac{ 9C }{ 5 }=F-32\]

Answer 37

Your goal is to solve for F. You must isolate F on the right side of your equation. How would you do this? Solve for F, please.

Answer 38

add 32

Answer 39

add 32 to both sides. Do this now, please.

Answer 40

How would you add it to your fraction???

Answer 41

Write 9C/5 and then write "+32" after it.

Write out your whole new equation now, please.

Answer 42

9C/5 + 32 = F

Answer 43

Right. That's your formula. Does it match any of your answer choices?

Answer 44

Brooke?

Answer 45

She's offline