Question

help please -12>-36-8x

Answer 1

Do you know how to start this? @Kathy_morales13

Answer 2

\(\huge{-12>-36-8x}\)

First we need to have the variable only on one side....so we need to add 36 to both sides so we can cancel it out and have it on the other side...

\(\huge{-12+36>(-36+36)-8x}\)

Answer 3

i have to solve for x

Answer 4

Yes we do. The equation typed above will isolate the variable so we can find x.

Answer 5

okay

Answer 6

So you would need to simplify it...

\(\huge{-12+36>(-36+36)-8x}\)

Answer 7

Okay

Answer 8

is the answer -32 ?

Answer 9

Not quite....We need to get the x to itelf....so we first would add 36 to each side to get the real number to one side...

\(\LARGE{-12+36>(-36+36)-8x \rightarrow \color{red}{ 24>-8x}}\)

So now we need to get the varible to itself....we would need to divide by -8 on both sides in order to do that...

\(\huge{\frac{24}{-8}>\frac{-8x}{-8}}\)

What would x equal after the division?

Answer 10

-3?

Answer 11

Correct :) So your answer would be \(\LARGE{x>-3}\)

Answer 12

haha thank you :)

Answer 13

np :)