Question

Quick Help please? (question inside)

Answer 1

Okay well. First plug in 4 to g(x)

Answer 2

What do you get?

Answer 3

g(4)=x^2

Answer 4

Yes so then plug in the number 4 into x^2

Answer 5

16

Answer 6

Yep. So then plus in that number, 16, to f(x)

Answer 7

f(16)=16-3

Answer 8

\[x^{-3} = \frac{ 1 }{ x^3 }\]

Answer 9

So plug in 16 into \[\frac{ 1 }{ x^3 }\]

Answer 10

So, what do you think the solution would be?

Answer 11

@iTz_Sid

Answer 12

Haha, why dont you tell me. Plug in the number 16.\[\frac{ 1 }{ (16)^{3} }\] Use a calculator

Answer 13

I did but I got 1/4096

Answer 14

\[\frac{ 1 }{ 4096 }\]

Answer 15

Hm... I think i messed up somewhere... lol

Answer 16

@zepdrix Help! D:

Answer 17

At 1st we must find the value of g(x) when x= 4 that would be indeed 16
And then substitute x= 16 in the function f(x) so
16^-3 that would equal to 1/16^3
I don't think you messed-up

Answer 18

Oh wait f(g(x))
is\[(x^2)^{-3}\]

Answer 19

Hm... that would be the same as \[x^{-6} = \frac{ 1 }{ x^6 }\]

Answer 20

It should be the same...

Answer 21

I have a question is it x^-3 or x-3
Because if it it x-3 it would explain the option 13 which would be the right one

Answer 22

=1/4^6

ya this is weird D:
I think someone made a boo boo writing this problem.

Answer 23

Lmfao

Answer 24

yaaa x-3 would make sense :D

Answer 25

Indeed

Answer 26

Oh thats probably it... lol

Answer 27

So It'd be 13, correct?

Answer 28

Yes, it should be.