If y=cos x, what is y^6 (x)
You mean \(\large\rm y^{(6)}(x)\) yes? As in 6th derivative?
Yes
Take some derivatives, look for a pattern :D
Err I should say this... when they give you a similar type problem and ask you to find \(\large\rm y^{(108)}(x)\), then it's imperative that you recognize a pattern, because you don't want to take 108 derivatives.
But in this case, taking 6 derivatives in a row should be pretty easy.
Do you remember your sine and cosine derivatives?
Well I know that sinx=cos x and cosx=-sinx. Is this what what mean?
Yes.\[\large\rm \sin x\quad\to\quad \cos x\quad\to\quad-\sin x\quad\to\quad-\cos x\quad\to\quad \sin x\]
Is it the same as f(x)=x^(2) which equals 2x?
I'm not sure what you're asking..
Sorry Im looking at something else.
Anyway, notice that the trig derivatives come full circle after taking 4 of them. See how I started with sine and ended with sine after 4 derivatives?
Yes
So if you take 4 derivatives of cosine, you'll get back to cosine. Which means we really only need to take 2 derivatives. 6 derivatives of cosine is the same as 2 derivatives of cosine.
Oh okay so how would that look in terms of the problem?
\[\large\rm y=\cos x\]\[\large\rm y'=-\sin x\]\[\large\rm y''=-\cos x\]\[\large\rm y'''=\sin x\]\[\large\rm y^{(4)}=\cos x\]So four derivatives got us back to cosine. Take two more derivatives.
so y^(5)=-sin x y^(6)=-cox x ?
Yay good job
Wow really! Thank you for explaining that for me.
np
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