Can I get help on how to start solving this, along with the formula? Studying for Midterm tomorrow. Aimee currently has an account balance of $2,199.21. She opened the account 9 years ago with a deposit of $1,668.17. If the interest compounds quarterly, what is the interest rate on the account?
@zepdrix
@Awolflover1 @samanthagreer @quickstudent
What do you think it is
The formula?
or?
the anwer
i don't know...
I don't even know what formula to use.
Anything appreciated.
\[\large\rm A=P\left(1+\frac{r}{n}\right)^{nt}\] P is our principle or starting amount r is the interest rate n is the number of compoundings per period t is the period (number of years in this case) A is the amount we end up with.
They gave us a bunch of the pieces, and they expect us to solve for the unknown piece, which is r in this case.
in this situation, just for personal preference, can we use x?
For your unknown? Sure!\[\large\rm A=P\left(1+\frac{x}{n}\right)^{nt}\]
okay lemme plug everything in and try to solve, then can i check back?
Do you understand the value of each part that they gave us? t = 9 years P = 1668.17 n is a little tricky. quarterly means we'll be calculating it 4 times a year, ya?
Oh!!!! I tried to solve this with that formula!
yes i do!
correct!
the problem i came to was when we get \[2,199.21=1668.17(1+\frac{ x }{ 4 })^{36}\]
the \[\frac{ x }{ 4 }\] How do i deal with that thing?
@zepdrix
Ahh sorry was making a sammich >.<
no youre fine! Just checkn!
\[\large\rm 2,199.21=1668.17\left(1+\frac{x}{4}\right)^{36}\]Hmm bunch of weird stuff being applied to our x. We'll have to undo all of this, one step at a time. Notice this big block of stuff is being `multiplied` by 1668.17. So we'll have to `divide` both sides by this value to undo that step.
Because of order and operations duh!
i should've know that to begin lol
\[\large\rm \frac{2199.21}{1668.17}=\left(1+\frac{x}{4}\right)^{36}\]Ok with that step?
1.3183?
\[\large\rm 1.318=\left(1+\frac{x}{4}\right)^{36}\]Ok. So the `division` took care of that `multiplication`. Now we need to somehow deal with this `exponent`. Do you remember how to get rid of an exponent?
oh god, i dont :-(
We undo `powers` using `roots`. For example if we had an equation like this: \(\large\rm x^2=4\) We would undo the `square` on the x by taking a `square root` of each side.\[\large\rm \sqrt{x^2}=\sqrt4\]\[\large\rm x=\pm2\]
We have a 36th power, so we'll need to take a 36th root of each side.
im horrible at roots, but i think i remember some things about htat stuff. I wouldn't know how to continue from here though
\[\large\rm \sqrt[36]{1.318}=\left(1+\frac{x}{4}\right)\]So we'll take a 36th root of each side, that will undo the 36 power on the right side of the equation.
If you use your calculator, you should get something like 1.007699 on the left side of the equation. Maybe we'll round that to 1.008
\[\large\rm 1.008=\left(1+\frac{x}{4}\right)\]
could we solve without roots?
i think i have the answer though : 3.1% ?
I'm coming up with x=0.032 which is 3.2% (But that was with the rounded values, so maybe yours is more accurate).
without roots? Hmm I don't think so :o
Yayyy team, we did it! :)
Thank you for your help!
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