Question

Derivative of f(x)=(x^3-3x^2+4)/x^2

Answer 1

How would I do the constant part?

Answer 2

Would it just be 4x^-2 or...4x^2

Answer 3

the first because the negative would be negative when you move it to the top
\[\frac{ a }{ x } =ax^{-1}\]
(a is a constant)

Answer 4

first one *

Answer 5

the first one because the exponent would be negative when you move it to the top
**typos -_-

Answer 6

Okay, so would it be x-3+4x^-2 ?

Answer 7

yes

Answer 8

OKay so the derivative would be ...
1-8x^-3 ?

Answer 9

good!!

Answer 10

So then it would be if you put if back into form...
1-8/(x^3) ?

Answer 11

\[1-\frac{8}{x^3}\] yes correct. good job! :D

Answer 12

Thank you !!

Answer 13

yw! :=)) o^_^o