There are two solutions to the equation \log(30 x) + \log(x-1) = 1log(30x)+log(x−1)=1. Find the larger of the two solutions.
log 30x + log (x-1) = 1 there are two samw equations so why ?
same - equations - sorry
do you know this property of logarithms ? log a + log b = log a*b
can using this in case of your exercise ?
it just got repeated sorry.
ok np but can using this formula in case of your exercise ?
a=30x and b=(x-1)
u can use anything to solve it but yeah iam familiar with it
but what im confused abut is the 2 solutions that they are reffering to
using this formula you get log 30x +log (x-1) =1 log [30x(x-1)] = 1 log (30x^2 -30x) =1 do you know how many is the base of this logarithm noted by log ?
Loser how many is the base of this log. just bc. i ve learned it 2 by 35 years ago here in Europe and here in OS have wrote me that is 10 ?
ok- ty
so in this case we can rewriting the 1 like log 10
and will get this equation log (30x^2 -30x) =1 log (30x^2 -30x) = log 10 30x^2 -30x = 10 do you can continue it now ?
subtract from both sides 10 and will get 30x^2 -30x -10 = 0 can you solving this quadratic ?
factorize out the 10 and will get 10(3x^2 -3x -1) = 0 divide both sides by 10 and will get 3x^2 -3x -1 = 0 can you solving it now for x ?
do you know formula of discriminant ?
please collaborate
i was trying to solve the last equation you wrote. sorry
yeah i do
3x^2 -3x -1 = 0 so can you solving this quadratic ?
let me solve it and confirm wiht u
ok. but please write here your work
discriminant D = ?
step by step please
ok i just solved it using the formula b+/= ....
and i got 2 values for x x=1.26 x= -0.263
i dont know if thats right or wrong
D = b^2 -4ac is the formula of discriminant
3x^2 -3x -1 = 0 how many you have got the value for discriminant ?
21
D = 9 +12 = 21 yes is right so than x_1,2 = ?
im confused what are using d for
D is the discriminant
after you get the value of discriminant how you get the roots x_1,2 ?
idk
so how you ve got these two values ?
ok. try using this x_1,2 = (-b +/- sqrt(D) )/2a
3x^2 -3x -1 = 0 b = ?
D = b^2 -4ac = ?
how you get the value of discriminant ?
3x^2 -3x -1 = 0 a=3 b=-3 c=-1 yes ?
bc. there are ax^2 +bx +c = 0
so can you calculi now the x_1,2 = ?
x_1,2 = (-b +/- sqrt(D) )/2a
ok ur method is different
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