I don't get how to answer "h(x)= -7x; h(x) = 63" to find the value of x. I know that h(x) means that h is a function of x, and to solve the single problems like f(x) = x+6, buts that's all. Can y'all help me :)
Strikes me as a strange problem. Here your function h(x) is defined in two different ways: h(x) =-7x and h(x) = 63. h(x) obviously equals h(x), so one could conclude that -7x=63. What is the value of x that satisfies this?
Exactly. Let me send a link to show.
Show what?
Since for some reason it doesn't work, I'll write down. In Exercises 13-18, find the value of x so that the function has the given value. 13. h(x) = -7x; h(x) =63 14. t(x) = 3x; t(x) = 24 Etc.....
You have to solve the value of x
for h(x) = -7x; h(x) =63 they are saying if h(x) is 63 , and h(x) is -7x then -7x = 63 and we want to know what "x" value causes h(x) to be 63 in this case, divide both sides by -7 \[ \frac{-7}{-7} x = \frac{63}{-7} \\ x = -9 \] as a check: using h(x)= -7x then h(-9) = -7*-9 = 63 so it checks out.
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