Question

please hep
what's the value of
a–2=3+6a/3

Answer 1

I think 3

Answer 2

a=-5
So that means that -5-2=3+6x-5-/3 so your value should be -7.

Hope this helps :)

Answer 3

so a=-5 and the means a's value is -5 right i'm sorry i'm still trying to understand this stuff

Answer 4

Are you finding the value of the whole equation or just A?

Answer 5

is the problem
\[ a-2 = \frac{3+6a}{3} \]?

Answer 6

yes

Answer 7

just a

Answer 8

as you know, the right side can be written
\[ \frac{3+6a}{3} = \frac{3}{3} + \frac{6}{3} a \]
can you simplify that ?

Answer 9

that would 9/3a right

Answer 10

what do you get for
\[ \frac{3}{3} + \frac{6}{3} a \]?

Answer 11

order of operations: first do the divide 3 / 3 is what ?
and 6/3 is what ?

Answer 12

3/3 is 0 and 6/3 is 2

Answer 13

right?

Answer 14

6/3 is 2

but anything divided by itself is 1 (not 0)

Answer 15

oh sorry I messed up there

Answer 16

is 3/3 is 1 and 6/3 is 2?

Answer 17

ok so we figured out that
\[ \frac{3+6a}{3} = 1+2a \]
so now the problem is
\[ a-2 = \frac{3+6a}{3} \\
a-2 = 1+2a\]
after we simplified the right side

Answer 18

ok so what's nect?

Answer 19

a-2 = 1+2a

I would add -a to both sides. can you do that ?

Answer 20

then that would be 2 = 1+ 2 right?

Answer 21

you start with
a-2 = 1+2a
then you write -a on both sides, like this
a-a -2 = 1+2a - a

Answer 22

ok so then that = 2 = 1+ 2

Answer 23

a-a -2 = 1+2a - a

a-a is 0 (you have 1 a take away 1 a, leaves no a's)

so it is

0 - 2 = 1 + 2a - a

0-2 is just -2
so you have

-2 = 1+2 a - a

on the right side you have 2 a's take away 1 a. how many a's are left ?

Answer 24

none

Answer 25

???

Answer 26

two apples take away 1 apple leaves 1 apple
the same for
2a - a = a
so you have
-2 = 1+2 a - a
becomes
-2 = 1 + a
finally add -1 to both sides:
-2-1 = 1-1 + a

Answer 27

so it's -2=1?