Question

In physics, if a moving object has a starting position at s 0, an initial velocity of v 0, and a constant acceleration a, then the position S at any time t > 0 is given by:

S = at 2 + v 0 t + s 0.

Solve for the acceleration, a, in terms of the other variables. For this assessment item, you can use ^ to show exponents and type your answer in the answer box, or you may choose to write your answer on paper and upload it.

Answer 1

Sorry i misread the question
its just algebra
rearrange to make a the subject of the equation

Answer 2

s = at^2 + v0 t + s0
subtract Vo t and s0 from both sides of the equation
s - v0 t - s0 = at^2

now divide both sides by t^2 and you have the answer

Answer 3

how would i divide from both sides of the equation ? @welshfella

Answer 4

divide each term by t^2
the first bit on left side would be s / t^2 then do same to other 2 terms

dividing at^2 on right side by t^2 will give a , which is what you want

Answer 5

s/t^2 - _____ - ______ = a

can you fill in the blanks?

Answer 6

just divide v0 t by t^2 and s0 by t^2

Answer 7

s/t^2-s - v0 t - s0 = at^2?

Answer 8

No you haven't done the division

Answer 9

I did the right side already its a

Answer 10

im so confused

Answer 11

s/t^2-s - v0 t^2 - s0t^2 = at^2

Answer 12

s divided by t^2 = s / t^2
in the same way
v0 t divided bt t^2 = v0 t / t^2

Answer 13

s / t^2-v0 t / t^2

Answer 14

yea now do the same to s0 and at^2

Answer 15

s / t^2-v0 t / t^2 s0/t^2

Answer 16

is s / t^2-v0 t / t^2 s0/t^2 the answer?

Answer 17

s - V0 t - s0 = at^2 To get a on its own on right side we divide by t^2 :-

s/t^2 - V0 t / t^2 - s0 / t^2 = at^2 / t^2 Now simplify
s/t^2 - v0 / t - s0/t^2 = a

Answer 18

v0 t / t^2 = v0 / t beacuse t will divide into t^2 to give t on the bottom

Answer 19

OK

we have solved the original equation for a.

a = s/t^2 - v0 / t - s0 /t^2

Answer 20

- I flipped the equation over so that a is on left side.

Answer 21

gotta go