Question

Trig question

Answer 1

\[\cos ^{2}(-\frac{ 4\pi }{ 3 })-\csc ^{2}(\frac{ 9\pi }{ 8 })+\cot ^{2}(-\frac{ 15\pi }{ 8 })\]

Answer 2

*leaves*

Answer 3

@mathmale

Answer 4

can i have your number

Answer 5

no.

Answer 6

can i ave ur number then?

Answer 7

still no

Answer 8

XD

Answer 9

@jiteshmeghwal9

Answer 10

\[\cos^2\left( \frac{-4 \pi}{3} \right)-cosec^2\left( \pi + \frac{\pi}{8} \right)+\cot^2\left( \frac{15 \pi }{8} \right)\]

Answer 11

actually \[\cot (\frac{-15 \pi}{8})=\cot (\frac{15 \pi}{8})\]

Answer 12

& \[\cos (\frac{-4 \pi}{3})=\cos (\frac{4 \pi}{3})\]

Answer 13

now coming back to our question

Answer 14

\[\cos^2(\frac{4 \pi}{3})-cosec^2(\pi + \frac{\pi}{8})+ \cot^2(\frac{15 \pi}{8})\]\[\cos^2(\frac{4 \pi}{3})-cosec^2 (\frac{\pi}{8})+\cot^2(2 \pi -\frac{\pi}{8})\]\[\cos^2(\frac{4 \pi}{3})-\left( cosec^2(\frac{\pi}{8})-\cot^2(\frac{\pi}{8}) \right)\]

Answer 15

\[cosec^2a-\cot^2a=1\]so\[cosec^2(\frac{\pi}{8})-\cot^2(\frac{\pi}{8})=1\]

Answer 16

therefore \[\cos^2 (\frac{4 \pi}{3})-1=-\sin^2(\frac{4 \pi}{3})\]

Answer 17

You are so awesome @jiteshmeghwal9 !!! xD

Answer 18

thanx