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OpenStudy (vheah):
Finding the area of the region: Setting up an integral in this sine curve. File attached
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likeabossssssss (likeabossssssss):
ehat do u think it is?
likeabossssssss (likeabossssssss):
what
OpenStudy (vheah):
So I just want to make sure that this is the right equation for the area of the region: \\[\int\limits_{-\Pi/2}^{3\Pi/2} (\sin(x) +1)/(x^{2} +1 )\]
OpenStudy (vheah):
@likeabossssssss is that the right definite integral?
OpenStudy (vheah):
is that the right definite integral that solves the area of the region?
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likeabossssssss (likeabossssssss):
ummmmm im srry but i dk :(
likeabossssssss (likeabossssssss):
here i will tag some 1 for u :) @welshfella
OpenStudy (vheah):
thank you c:
likeabossssssss (likeabossssssss):
np :)
OpenStudy (jango_in_dtown):
hello. @vheah how did you get the function?
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OpenStudy (vheah):
@jango_IN_DTOWN , it was given to me by our teacher. I believe we have to find the area between -pi/2 and 3pi/2
OpenStudy (dumbcow):
yes the limits are right if you want the region between the roots of the equation
OpenStudy (vheah):
okay and does the function f(x) inside the integral stay the same? @dumbcow
OpenStudy (jango_in_dtown):
ok.... then proceed.
OpenStudy (dumbcow):
yes , If the question is , Find area beneath curve :)
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OpenStudy (vheah):
okay. I wasn't sure if the function would change in any way or not. Thank you! :) @dumbcow
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