find the absolute max of f(x) on [-1,1]
\[f(x)=2-x \sqrt{1-x^2}\]
i got 2 but apparently that's wrong
how did u get 2?
i took the derivative and set it equal to 0 to solve for c/x and then used that value and plugged it into the original equation to find the y value of 2
yeah finding the derivation and setting it equal to 0 will give you the value of "x" for which the function will attain either its MIN or MAX value and to find either its min or max you have to go for double derivative BUT you should also note that the "x" that you get from here may either lie in the given interval [-1,1] OR MAYBE it won't
they were actually just the endpoints. And why would i use the second derivative? if that's what double derivative is lol
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