Question

HELP PLEASE! D:

Answer 1

I need help with #5.

Answer 2

Here is my work.

Answer 3

Idk, it looks right to me. D:

Answer 4

Hm?

Answer 5

oooops

it's shiτ

Answer 6

???

Answer 7

well, if it takes 26N to stretch it by 6cm, then \(k = \dfrac{26}{0.06} = \dfrac{13}{0.03} \frac{N}{m}\)

The work to stretch it by 3cm is then equal to the energy stored in the spring: \(= \dfrac{1}{2} k x^2 = \dfrac{1}{2} \dfrac{13}{0.03} (0.03)^2\)

that's pretty much all there is to it

Answer 8

I got 0.19 as my answer. And got it wrong :/

Answer 9

type it into your calculator again

Answer 10

Or nvm :-))

Answer 11

Ugh, Now i only have 1 attempt left at the right answer. Can someone please help? :(

Answer 12

Which course are you in? calculus 2 or differential equation?

Answer 13

Calculus 2

Answer 14

ok. Just want to know!! :)

Answer 15

Do you know how I can solve this?

Answer 16

I don't promise anything, but will try all my best.

Answer 17

no pressure

Answer 18

to me, k is what Irishboy said, just 26/0.06
and f(x) is just kx, and the limit is from 0 to 0.03.

Answer 19

pas de pressure

Answer 20

oh, it says you have to have it upto 2 decimal points, so, your answer should be 0.20

Answer 21

LOL!!

Answer 22

I saw a lot of cases like this. The computer is so sensitive. I don't know!! :)

Answer 23

Wow...... lmao. Thanks xD

Answer 24

did you get it right?