Question

Help me solve this equation.

Answer 1

What are the solutions to this equation
\[0 = -2\cos(x)-2\cos^2(x)-2\sin^2(x)\]

I got the solution to be x = π
but another solution is x = 5π/3
How did they get 5π/3??

Answer 2

Can you show us what you've done?

Answer 3

hey wait

Answer 4

I factored out the -2
0 = -2(cos(x) + cos^2(x) + sin^2(x))
-2(cos(x) + 1) = 0
cos(x) = -1
x = π

Answer 5

if that's the question you got it right, but I think you have misread the question, maybe there is a cos(2x) or sin(2x)? check it out

Answer 6

No there isn't...

Answer 7

so x=5pi/3 definitely is not an answer

Answer 8

that means cos( 5π/3)=-1, do you believe that this is right?

Answer 9

Do you know what you are talking about?

Answer 10

yes I know :))

Answer 11

\(0 = -2\cos(x)-2\cos^2(x)-2\sin^2(x)\)

\( 0 = -2\cos(x)-2( \cos^2(x)+2\sin^2(x))\)

\( 0 = -2\cos(x)-2\)

\( \cos(x) = -1\)

and when does the \(\cos \) curve hit -1?