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Mathematics 25 Online
OpenStudy (puppylove):

inequality help?? will give medal?

OpenStudy (puppylove):

solve each inequality. then check your solution. 6. -5x-(2x+3)>=1

OpenStudy (puppylove):

@ShadowLegendX ?

OpenStudy (brooke..help00):

Is that 6. a part of the inequality or the number of your question?

OpenStudy (puppylove):

its just the number of the question

OpenStudy (brooke..help00):

\[-5x - \left( 2x + 3 \right) \ge 1\]

OpenStudy (brooke..help00):

Correct inequality?

OpenStudy (puppylove):

yes

OpenStudy (brooke..help00):

There is nothing you can do in the (----------) \[-5x - 2x + 3 \ge 1\]

OpenStudy (brooke..help00):

Add like terms together \[-7x + 3 \ge 1\]

OpenStudy (brooke..help00):

Subtract 3 from both sides \[-7x \ge -2\]

OpenStudy (brooke..help00):

Ok- hold on I messed up somewhere I think :/ Let me double check my work.

OpenStudy (puppylove):

where did -2 come from? I'm not good at inequalitys

OpenStudy (shadowlegendx):

1 - 3 = -2

OpenStudy (puppylove):

can you walk me through it please?

OpenStudy (shadowlegendx):

I'm cooking rn, but I can multi task xD Let me throw some chives in and Ill be with you

OpenStudy (puppylove):

oh ok I'm sorry thank you xD

OpenStudy (shadowlegendx):

Question, is the symbol "greater than" or "greater than or equal to" ???

OpenStudy (brooke..help00):

I wrote the correct inequality earlier if you want to take a look.

OpenStudy (shadowlegendx):

I see "-5x-(2x+3)>=1" and your use of "greater than or equal to"

OpenStudy (puppylove):

yes its suppose to be this > over the equal sign =

OpenStudy (brooke..help00):

\[-5x-(2x+3)\ge 1\]

OpenStudy (shadowlegendx):

\[-5x-(2x+3)\ge =1\] First, lets distribute the -1 to 2x and 3, the numbers inside of the parentheses. \[-5x-2x -3\ge =1 \] Like terms \[-7x - 3 \ge =1\] Add 3 to both sides \[-7x \ge = 4\] Divide the entire inequality by -7 to isolate x. Not that the 7 is negative. \[x \le \frac{ 4 }{ -7 }\] When you divide or multiply an inequality by a negative number, the sign changes

OpenStudy (shadowlegendx):

Note*

OpenStudy (brooke..help00):

Oh yeah, That is where I messed up... Thanks @ShadowLegendX

OpenStudy (shadowlegendx):

Yeah, distributing the -1

OpenStudy (shadowlegendx):

Do we have a solution to check the inequality with?

OpenStudy (puppylove):

ohh ok. thank you so much! I appreciate this so much! I have some more .....like 9 more.... xc I'm trying to help my brother but I'm no good at this

OpenStudy (puppylove):

\[\frac{ 4 }{ -7 }\] is the solution?

OpenStudy (shadowlegendx):

Is there a set of points, given in parentheses? Like (x,y) ??

OpenStudy (puppylove):

no

OpenStudy (shadowlegendx):

A graph perhaps?

OpenStudy (puppylove):

no it just says solve the inequlity. then check your solutions.

OpenStudy (shadowlegendx):

Hmm, can you upload the image perhaps?

OpenStudy (puppylove):

its on paper

OpenStudy (shadowlegendx):

Here is the confusing part for me. Usually, when they ask you to check "your solution" it's a set of points

OpenStudy (shadowlegendx):

We input them into the inequality, to see check the solution, to see if it's corret

OpenStudy (shadowlegendx):

correct*

OpenStudy (puppylove):

do I convert the fraction to a decimal ?

OpenStudy (shadowlegendx):

No, usually teachers like them in fractions, unless specified to be in decimal form.

OpenStudy (puppylove):

its not specified. I just thought it would be easier to check if it was in decimal form

OpenStudy (shadowlegendx):

It's actually easier to check in fraction form, though I doubt you'd want me to explain why xD

OpenStudy (shadowlegendx):

Is problem 6, connection to any of the previous problems? Perhaps you got a solution from them

OpenStudy (puppylove):

no its not. its just a list of inequalities and it says to solve and check the solutions

OpenStudy (shadowlegendx):

Oh, mb, you were right when you first asked. Solution is 4/-7. You just have to input it

OpenStudy (shadowlegendx):

Do you know how to do that?

OpenStudy (puppylove):

no I'm not sure I'm sorry

OpenStudy (shadowlegendx):

Input 4/-7 into the original inequality

OpenStudy (shadowlegendx):

\[ -5(\frac{ 4 }{ -7 }) -(2(\frac{ 4 }{ -7 })+3) \ge=1\]

OpenStudy (shadowlegendx):

Like that

OpenStudy (puppylove):

ohh ok thank you

OpenStudy (shadowlegendx):

Then solve

OpenStudy (shadowlegendx):

\[\frac{ -20 }{ -7 } - ( \frac{ 8 }{ -7 } + 3 \ge 1\]

OpenStudy (shadowlegendx):

\[\frac{ -20 }{ -7 } - ( \frac{ 8 }{ -7 } + 3) \ge 1\]

OpenStudy (puppylove):

wait how did you get 8 over -7

OpenStudy (shadowlegendx):

Distribute the -1 \[\frac{ 20 }{ 7 } + \frac{ 8 }{ 7 } -3 \ge 1\]

OpenStudy (shadowlegendx):

\[2(\frac{ 4 }{ -7 }) = \frac{ 2 }{ 1 } \times \frac{ 4 }{ -7 }\]

OpenStudy (puppylove):

I'm so sorry I do not understand now

OpenStudy (shadowlegendx):

Let me know what you don't understand specifically

OpenStudy (puppylove):

how you got -20 over -7 and 8 over -7

OpenStudy (shadowlegendx):

\[-5(\frac{ 4 }{ -7 }) = \frac{ -20 }{ -7 } = \frac{ 20 }{ 7 }\]

OpenStudy (shadowlegendx):

\[2(\frac{ 4 }{ -7 }) = \frac{ 8 }{ -7 }\]

OpenStudy (shadowlegendx):

Remember, we are inputting our solution, which is 4/-7, to see of our inequality is true

OpenStudy (shadowlegendx):

\[\frac{ 20 }{ 7 } + \frac{ 8 }{ 7 } -3 \ge 1\] Like terms \[\frac{ 28 }{ 7 } - 3 \ge 1\] Simplify 28/7 and add 3 to both sides \[4 \ge 4\]

OpenStudy (shadowlegendx):

7 goes into 28. 4 times

OpenStudy (shadowlegendx):

4 is greater than or equal to 4, which is correct. Therefore 4/-7 is a solution to our inequality

OpenStudy (puppylove):

ohh ok omg thank you so much your the best

OpenStudy (shadowlegendx):

No problem

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