inequality help?? will give medal?
solve each inequality. then check your solution. 6. -5x-(2x+3)>=1
@ShadowLegendX ?
Is that 6. a part of the inequality or the number of your question?
its just the number of the question
\[-5x - \left( 2x + 3 \right) \ge 1\]
Correct inequality?
yes
There is nothing you can do in the (----------) \[-5x - 2x + 3 \ge 1\]
Add like terms together \[-7x + 3 \ge 1\]
Subtract 3 from both sides \[-7x \ge -2\]
Ok- hold on I messed up somewhere I think :/ Let me double check my work.
where did -2 come from? I'm not good at inequalitys
1 - 3 = -2
can you walk me through it please?
I'm cooking rn, but I can multi task xD Let me throw some chives in and Ill be with you
oh ok I'm sorry thank you xD
Question, is the symbol "greater than" or "greater than or equal to" ???
I wrote the correct inequality earlier if you want to take a look.
I see "-5x-(2x+3)>=1" and your use of "greater than or equal to"
yes its suppose to be this > over the equal sign =
\[-5x-(2x+3)\ge 1\]
\[-5x-(2x+3)\ge =1\] First, lets distribute the -1 to 2x and 3, the numbers inside of the parentheses. \[-5x-2x -3\ge =1 \] Like terms \[-7x - 3 \ge =1\] Add 3 to both sides \[-7x \ge = 4\] Divide the entire inequality by -7 to isolate x. Not that the 7 is negative. \[x \le \frac{ 4 }{ -7 }\] When you divide or multiply an inequality by a negative number, the sign changes
Note*
Oh yeah, That is where I messed up... Thanks @ShadowLegendX
Yeah, distributing the -1
Do we have a solution to check the inequality with?
ohh ok. thank you so much! I appreciate this so much! I have some more .....like 9 more.... xc I'm trying to help my brother but I'm no good at this
\[\frac{ 4 }{ -7 }\] is the solution?
Is there a set of points, given in parentheses? Like (x,y) ??
no
A graph perhaps?
no it just says solve the inequlity. then check your solutions.
Hmm, can you upload the image perhaps?
its on paper
Here is the confusing part for me. Usually, when they ask you to check "your solution" it's a set of points
We input them into the inequality, to see check the solution, to see if it's corret
correct*
do I convert the fraction to a decimal ?
No, usually teachers like them in fractions, unless specified to be in decimal form.
its not specified. I just thought it would be easier to check if it was in decimal form
It's actually easier to check in fraction form, though I doubt you'd want me to explain why xD
Is problem 6, connection to any of the previous problems? Perhaps you got a solution from them
no its not. its just a list of inequalities and it says to solve and check the solutions
Oh, mb, you were right when you first asked. Solution is 4/-7. You just have to input it
Do you know how to do that?
no I'm not sure I'm sorry
Input 4/-7 into the original inequality
\[ -5(\frac{ 4 }{ -7 }) -(2(\frac{ 4 }{ -7 })+3) \ge=1\]
Like that
ohh ok thank you
Then solve
\[\frac{ -20 }{ -7 } - ( \frac{ 8 }{ -7 } + 3 \ge 1\]
\[\frac{ -20 }{ -7 } - ( \frac{ 8 }{ -7 } + 3) \ge 1\]
wait how did you get 8 over -7
Distribute the -1 \[\frac{ 20 }{ 7 } + \frac{ 8 }{ 7 } -3 \ge 1\]
\[2(\frac{ 4 }{ -7 }) = \frac{ 2 }{ 1 } \times \frac{ 4 }{ -7 }\]
I'm so sorry I do not understand now
Let me know what you don't understand specifically
how you got -20 over -7 and 8 over -7
\[-5(\frac{ 4 }{ -7 }) = \frac{ -20 }{ -7 } = \frac{ 20 }{ 7 }\]
\[2(\frac{ 4 }{ -7 }) = \frac{ 8 }{ -7 }\]
Remember, we are inputting our solution, which is 4/-7, to see of our inequality is true
\[\frac{ 20 }{ 7 } + \frac{ 8 }{ 7 } -3 \ge 1\] Like terms \[\frac{ 28 }{ 7 } - 3 \ge 1\] Simplify 28/7 and add 3 to both sides \[4 \ge 4\]
7 goes into 28. 4 times
4 is greater than or equal to 4, which is correct. Therefore 4/-7 is a solution to our inequality
ohh ok omg thank you so much your the best
No problem
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