Question

something (7kg) is dropped out of a building, falling for 6 seconds. How much work did gravity apply? how much power did gravity apply?

Answer 1

Work = Force x displacement
Force = mass x gravity
Power = work / time

Answer 2

following @hoot_hoot 's lead, you might wish to start with the equations of motion

gravity (g) exerts a constant force of 7g on the 7kg "something" over the displacement, and you need to know the displacement

there are so many different formulations of the same thing, but you might consider \( x = ut + \frac{1}{2} g t^2 = \frac{1}{2} g t^2\) as it's *dropped* and not thrown..... so its initial velocity can be assumed to be zero

here, \(x\) is the downward displacement

power is more problematic. it is instantaneous, in terms of time.

Power = work / time = Force x velocity