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I am confused with this help calculus problem.
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What is the maximum vertical distance between the line y = x+2 and the parabola y = x^2 for -1 <= x <= 2
I know that y2 - y1 = max, so I did x^2 - x - 2, then found the derivative when it equals 0. Which I got x = 1/2
What I don't get is that wouldn't that be the minimum? Because x^2 - x - 2 has a minimum, not a max.
Abhi yes you are right sorry
Actually the expression you made has a fault here
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Can you please explain?
When u draw the graph u will see that from x=-1 to x=2 the graph of y=x+2 is above the graph of y=x^2. So the vertical distance expression should be x+2-x^2
Ohh, so you always have to subtract the one that is below the graph correct?
Yes
Thank you.
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