Ask your own question, for FREE!
Mathematics 17 Online
OpenStudy (steve816):

I am confused with this help calculus problem.

OpenStudy (steve816):

What is the maximum vertical distance between the line y = x+2 and the parabola y = x^2 for -1 <= x <= 2

OpenStudy (steve816):

I know that y2 - y1 = max, so I did x^2 - x - 2, then found the derivative when it equals 0. Which I got x = 1/2

OpenStudy (steve816):

What I don't get is that wouldn't that be the minimum? Because x^2 - x - 2 has a minimum, not a max.

OpenStudy (jiteshmeghwal9):

Abhi yes you are right sorry

OpenStudy (jiteshmeghwal9):

Actually the expression you made has a fault here

OpenStudy (steve816):

Can you please explain?

OpenStudy (jiteshmeghwal9):

When u draw the graph u will see that from x=-1 to x=2 the graph of y=x+2 is above the graph of y=x^2. So the vertical distance expression should be x+2-x^2

OpenStudy (steve816):

Ohh, so you always have to subtract the one that is below the graph correct?

OpenStudy (jiteshmeghwal9):

Yes

OpenStudy (steve816):

Thank you.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!