Medal. Please help . , . The coordinates of the vertices of △ABC△ABC are A(−1,1)A(−1,1), B(−2,3)B(−2,3), and C(−5,1)C(−5,1). The coordinates of the vertices of △A′B′C′△A′B′C′ are A′(−1,−4)A′(−1,−4), B′(−2,−6)B′(−2,−6), and C′(−5,−4)C′(−5,−4). Which statement correctly describes the relationship between △ABC△ABC and △A′B′C′△A′B′C′ ? △ABC△ABC is congruent to △A′B′C′△A′B′C′ because you can map △ABC△ABC to △A′B′C′△A′B′C′ using a translation 5 units down followed by a reflection across the x-axis, which is a sequence of rigid motions. △ABC△ABC is congruent to △A′B′C′△A′B′C′ becaus
@563blackghost Do you think you could help me with one more? Its ok if you cant
Lets look at our coords...we'll analyze A and A'.... \(\huge\bf{(-1,1) \rightarrow (-1,-4)}\) We see that the `x-value` seems to stay as `-1` but the `y-value` changes....We see that the value does not just change the sign of the `y-value` but it changes the number this would only mean that this is a translation....so we would subtract 1 and -4 to find out how much a translation was made... \(\huge\bf{1 - (-4) = ?}\)
Remember when subtracting with a negative it will change to a positive... \(\huge\bf{1 - (-4) \rightarrow 1 + 4 =?}\)
5 . , .
Correct :) Now since it goes from `1 to -4` that would mean that the coords are translated DOWN `5 units`.....
Im quite confused. The rule applies to coord A and coord C but not to coord B.... \(\huge\bf{A(-1,1-5) \rightarrow (-1,-4)}\) \(\huge\bf{C(-5,1-5) \rightarrow (-5,-4)}\)
Can you type out the rest of your answer choices it seems only one was posted up.
Ok.
Please type out the other answer choices so I can see what rule works :)
can you use the draw and show a sketch to "see" the relationship
A. △ABC△ABC is congruent to △A′B′C′△A′B′C′ because you can map △ABC△ABC to △A′B′C′△A′B′C′ using a translation 5 units down followed by a reflection across the x-axis, which is a sequence of rigid motions. B. △ABC△ABC is congruent to △A′B′C′△A′B′C′ because you can map △ABC△ABC to △A′B′C′△A′B′C′ using a translation 3 units down followed by a reflection across the x-axis, which is a sequence of rigid motions
C. △ABC△ABC is not congruent to △A′B′C′△A′B′C′ because there is no sequence of rigid motions that maps △ABC△ABC to △A′B′C′△A′B′C′ . D. △ABC△ABC is congruent to △A′B′C′△A′B′C′ because you can map △ABC△ABC to △A′B′C′△A′B′C′ using a reflection across the x-axis followed by a translation 3 units down, which is a sequence of rigid motions.
this was a bit confusing finally realized the coordinates were all typed twice
Sorry e.e
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