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Mathematics 18 Online
OpenStudy (rowanwhitethorn):

Is the relation a function? (-11,3),(-8,12), (2,6), (5,4), (14,6), (16,4) Why or why not.

Directrix (directrix):

A relation is a set of points. If a relation is a function, then any value of x in the relation can be paired with exactly one value of y for that x value. -11 is paired with the y-value of 3. Look at the remaining ordered pairs. Do you see -11 used again as an x-value and paired with a different value of y from 3?

OpenStudy (rowanwhitethorn):

@Directrix No, 11 is not used again.

Directrix (directrix):

Correct. Do you see any value of x that is paired with two different y-values?

Directrix (directrix):

Function: A function is a set of ordered pairs in which each x-element has only ONE y-element associated with it.

Directrix (directrix):

Tip: {(1,2), (2, 4), (3, 5), (2, 6), (1, -3)} is NOT a function because of this: (1,2) ; (1, -3) The x of 1 is paired with two different y values.

Directrix (directrix):

@rowanwhitethorn Do you think the relation you posted is a function?

OpenStudy (seratul):

It is different with vice versa right? One y value can be in two different x values.

OpenStudy (rowanwhitethorn):

So, it's not a function, correct?

Directrix (directrix):

@rowanwhitethorn If it is not a function, then the same x is paired with two different y values. Which x value in the relation is paired with two different y values? (-11,3),(-8,12), (2,6), (5,4), (14,6), (16,4)

Directrix (directrix):

2 is paired with 6 14 is paired with 6. But, that is not what we are looking for. We are looking to see if there is a same x paired with different y values.

Directrix (directrix):

@rowanwhitethorn >So, it's not a function, correct? Try again.

OpenStudy (rowanwhitethorn):

@Directrix Is this correct: The relation is a function because the x-coordinate is not paired with any y-values.

Directrix (directrix):

Almost but not quite correct. The relation is a function because each x-element has only ONE y-element associated with it.

Directrix (directrix):

@rowanwhitethorn ^^^^^

OpenStudy (rowanwhitethorn):

@Directrix Okay, thank you so much for your help! I've been stuck on this question all night.

Directrix (directrix):

You are welcome.

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