x^x = 2 Solve for x
this can't be solved with "normal math".
It will be equal to 1.56
You can graph y=x^x and y=5, and look at the intersection point https://www.desmos.com/calculator x is about 2.129
I think the graph would show it more clear.
oh y=2 it is, sorry
Thanks, DanJS This is what I did.
Thank you for the medal!
You can put it into a closed form with something called the Lambert W function, which is defined as the inverse of \(f(x)=xe^x\). \[x^x=2\]\[x\ln x = \ln 2\]\[e^{\ln x}\ln x = \ln 2\]\[\ln x = W (\ln 2)\]\[x = e^{W(\ln 2)}\]\[x=\frac{\ln 2}{W(\ln 2)}\] Hey if you're willing to call \(\ln 2\) a number then certainly \(W (\ln 2)\) is a number right? :P
Kainui what would the number be mate
\[\frac{\ln 2}{W(\ln 2)}\] is the number
Thank Kainui. I understand the graphical method but I should've clarified I was looking for an algebraic solution, which I know would be outside of a typical maths course. Thank you all.
Yeah if you wanna learn more there are some fun exercises here to try out: http://www.had2know.com/academics/lambert-w-function-calculator.html and if you want to solve things like infinite power towers of what you have \(2=x^{x^{x^\cdots}}\) then you can check this out too: https://luckytoilet.wordpress.com/tag/product-log/
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