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Mathematics 19 Online
OpenStudy (sheriph05):

I am aware a set is Bounded if it has both upper and Lower bound and i know what a Limit point of a set is but how can i show that If S ⊂ R be a "bounded infinite set", then S' ≠∅

ganeshie8 (ganeshie8):

@eliesaab @zzr0ck3r

ganeshie8 (ganeshie8):

Hey this should be really easy. Simply consider the set \((upper~ bound ~of~ S, ~~\infty)\). Is it a subset of \(S\) ?

OpenStudy (eliesaab):

Another way of seeing it if S' is empty, then S=R and R is not bounded

ganeshie8 (ganeshie8):

That argument is elegant!

OpenStudy (sheriph05):

Thanks Guys

OpenStudy (sheriph05):

Both the sets [0,1] and (0,1) are infinite bounded subsets of R. The question is surely fairly trivial since R is unbounded (1) So partitioning R into subsets S and S' where S' is the null set and S is R is contradicts (1) How can i conclude this?

ganeshie8 (ganeshie8):

@eliesaab gave you an one line proof. It is the complete proof..

ganeshie8 (ganeshie8):

Here is the same proof with more words : (proof by contradiction) If S' is empty, then S=R and since R is not bounded, S is also not bounded. But it is given that S is bounded. So, S' cannot be empty.

OpenStudy (sheriph05):

Thanks for your help guys

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