Question

Medal and Fan

Factor completely 2c5 + 44c4 + 242c3.

2c3(c + 11)2
2(c + 11)2
2c3(c + 11)(c − 11)
2c3(c2 + 22c + 121)

Answer 1

Mikey: a reminder:

Correct way to express exponentiation: Factor completely 2c^5 + 44c^4 + 242c^3

Ambiguous (unclear): Factor completely 2c5 + 44c4 + 242c3

Answer 2

so i divide each by 2

Answer 3

Looking at 2c^5 + 44c^4 + 242c^3, I see right off that 2and c^3 are common to all terms of your expression. Yes, div. by 2, but also div. by c^3.

Answer 4

@AloneS

Answer 5

lol im soo lost

Answer 6

idk how to divide by c^3

Answer 7

think the answer is d tho

Answer 8

c^3
--- = 1
c^3

c^5
--- = c^2
c^3

Answer 9

so you subtract the exponents

Answer 10

Looks like you need to look up "rules of exponents" and practice applying them.

Answer 11

Yes. But I'd prefer you look up the rules, copy them down, use and learn them.

Answer 12

Just so that you know, I need to get off the 'Net now. But I'll be back on later. keep going. You don't need to wait for me.

Answer 13

okay