Ask your own question, for FREE!
Mathematics 16 Online
OpenStudy (ryleepaisley10):

What would be the most likely charge of an ion formed from an atom with the electron configuration: 1s22s22p5 (2 points) +1 -1 +3 -3

OpenStudy (ryleepaisley10):

@wolf1728 @mikey @brooke..help00

OpenStudy (mikey):

is this a test?

OpenStudy (ryleepaisley10):

No. It's questions that I missed, and I want to know the correct answers for my notes.

OpenStudy (mikey):

ahh okay

OpenStudy (sooobored):

well, the numbers represent electrons, specifically the number of electrons in the specific shell 1s- 2 electrons 2s-2 electrons 2p-5 electrons in order for the p shell to be full, you need 6 electrons, which is sort of how you create an ion, you remove or add electrons until you reach the nearest stable shell

OpenStudy (ryleepaisley10):

Could someone explain this question to me?

OpenStudy (ryleepaisley10):

Ok, gotcha.

OpenStudy (mikey):

well i would say its B That would be Fluorine im pretty sure. Fluorine has a -1 oxidation state.

OpenStudy (sooobored):

well, yes but why

OpenStudy (mikey):

@3mar

OpenStudy (ryleepaisley10):

I put D before and got it wrong.

OpenStudy (sooobored):

crap, its been a while since ive had to explain chemistry

OpenStudy (ryleepaisley10):

Its ok.. I do believe its B myself.

OpenStudy (sooobored):

essentially, in order to add or remove electrons onto or from an atom, it requires a certain amount of energy in the case of ions, you want to try to use the least amount of energy in order to create an ion adding 2 electrons onto an atom would require exponentially more energy than if you were to add only 1 and same for removing

OpenStudy (mikey):

was i right?

OpenStudy (sooobored):

yes but doesnt help if they come back and ask the same question

OpenStudy (3mar):

Well, I am here.

OpenStudy (mikey):

late

OpenStudy (mikey):

yeah well its midnight for me so i gtg ttyl

OpenStudy (3mar):

I was praying Al-owletr

OpenStudy (3mar):

Tell me the question please

OpenStudy (3mar):

Thank you for the medal!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!