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Mathematics 8 Online
OpenStudy (giovxnnx):

Please, answer with the full solution! Thanks for the help! Readings on a thermometer are normally distributed with a mean of 0C and a standard deviation of 1.00. What is the probability that a randomly selected thermometer reads: • Less than 0.53. • Greater than -0.11 • Greater than -1.11 • Between 1.00 and 2.25 • Between -2.28 and -1.76 • Between -1.33 and 1.86 • Greater than 1.71

OpenStudy (mhchen):

Do you know how to find the percentage of the distribution using z-scores? Once you have the percentages, those are your probability.

OpenStudy (giovxnnx):

I am asking for someone to kindly solve them for me, it is really important and I have a real reason to not being able to solve them by myself. I am sorry. Please, help Mhchen.

OpenStudy (owen3):

You can use a normal distribution calculator, which are on the web.

OpenStudy (owen3):

I can walk you through using the calculator.

OpenStudy (giovxnnx):

@owen3 I really did not understand a thing on how this calculator function and where I should put each number! Plus, I need to write down on paper the whole solution for each. Thanks anyway!

OpenStudy (owen3):

You can't really do it by hand, it involves an integral. You need a table or a calculator.

Directrix (directrix):

I found the z-score that corresponds with the .53 reading. z = (x - mean) / standard deviation z = (.53 - 0) / 1 z = .53 Go to Normal Distribution Area Under the Curve Table. Find .53. Read out the area under the curve to the left of z = .53. That is the probability. .7019 = area Roughtly, 70% of the time the thermometer will read less than .53.

Directrix (directrix):

To get the areas under the curve, I use the chart rather than the calculator.

Directrix (directrix):

Here is a place to read about the procedure. http://accounts.smccd.edu/moss/Personal/math_200/Lecture%20Notes/Chapter%206_2.pdf @giovxnnx

OpenStudy (mathmale):

"Please, answer with the full solution!" is totally inappropriate here. You can ask for guidance that will help you solve the problem yourself, but asking for a direct answer with no involvement of yourself is strictly a NO-NO.

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