Hey can someone help me with this tricky math equation? I'm a freshman doing Algebra 1.
(x+3) +1 = 2
Solving for x?
yes
Okay We will have to simplify the left side We can get rid of the parentheses since the parentheses are not being multiplied by another term So we have X + 3 + 1 = 2
I have the answers from a test guide that our teacher gave us... But I don't know how to get there. Here is the two answers. x=-2 and x=-4
are you sure its a parenthesis () and not absolute values | |
\[(x+3) +1 = 2\] We can remove the parentheses as @Will.H stated. \[x + 3 + 1 = 2\] Like terms, \[x + 4 = 2\] Subtract 4 from both sides \[x = -2\]
@sooobored good point
the are like two brackets
but I can't type them
Absolute values then
\[\left| x + 3 \right| + 1 = 2\]
Since there are 2 solutions
Like this right?
Ya you were right on the first one @ShadowLegendX
wait
we were told to do the opposite if it was adding we had to subtract. so wouldn't we need to subtract the 1?
Lets solve \[\left| x + 3 \right| + 1 = 2 \] Subtract 1 from both sides to isolate x \[\left| x + 3 \right| = 1\] Now we get two equations \[x + 3 = 1\] and \[x + 3 = -1\] Solving for the first one \[x + 3 = 1\] Subtract 3 from both sides \[x = -2\] Solving for the second one \[x + 3 = -1\] Subtract 3 from both sides \[x = -4\]
@ShadowLegendX brilliant work mate
thank you so much!!
You can tell that these are solutions to, \[\left| x + 3 \right| + 1 = 2\] Because if you substitute either of the solutions for x, and solve, you get 2.
now i remember how to do this!!! You are a big help thank you!!
No problem, glad I could help :)
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