help please
g(x) = x + 1 and h(x) = x 2 - 4
h[g(x)] = _____.
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OpenStudy (3mar):
May I help?
OpenStudy (braves12):
yes
OpenStudy (3mar):
Thanks
OpenStudy (3mar):
Do you know what does \[h[g(x)]\]mean?
OpenStudy (braves12):
no
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OpenStudy (3mar):
That means : h is a function of the function g(x)
i.e. replace every x in "h(x)" with the whole function "g(x)".
Write it yourself and show me please.
OpenStudy (3mar):
@braves12
OpenStudy (mathmale):
Your " x 2 - 4" is vague. Did you mean "x^2 - 4?" Please clarify this.
You are to find the "composition" of functions h(x) and g(x). Can you find examples of "composite functions" in your textbook or online reading materials?
OpenStudy (braves12):
yes it is "x^2 - 4 and no
OpenStudy (3mar):
So can you do what I mentioned above, braves12?
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OpenStudy (braves12):
what do u mean
OpenStudy (3mar):
I mean replace every x in the function h(x) and put g(x), i.e (x+1)
OpenStudy (braves12):
g(x) = x 2 - 4
OpenStudy (3mar):
\[h(x)=x^2-4\]
and
\[g(x)\]
OpenStudy (3mar):
\[g(x)=x+1\]
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OpenStudy (3mar):
\[h(x)=(g(x))^2-4=[(x+1)^2]-4\]
OpenStudy (3mar):
Got it?
OpenStudy (braves12):
yea kind of
OpenStudy (3mar):
Can you expand the parentheses and do math?
OpenStudy (braves12):
nope
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OpenStudy (3mar):
\[h(x)=(x+1)^2-4=x^2+2x+1-4=x^2+2x\]
OpenStudy (braves12):
ok
OpenStudy (3mar):
sorry
\[-3\]
OpenStudy (braves12):
what
OpenStudy (3mar):
I mean
\[h(x)=x^2+2x-3\]
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OpenStudy (3mar):
Did you get it?
OpenStudy (braves12):
nope
OpenStudy (3mar):
Where are you stuck?
OpenStudy (braves12):
when u expanded the parentheses
OpenStudy (3mar):
good!
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OpenStudy (3mar):
\[h(x)=(x+1)^2-4\]
start from here?
OpenStudy (braves12):
i dont know how to start from there
OpenStudy (3mar):
Welcome back!
OpenStudy (3mar):
@braves12
OpenStudy (braves12):
ok
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OpenStudy (3mar):
so where you want to start?
OpenStudy (braves12):
idk
OpenStudy (3mar):
Do you have a Skype Id?
OpenStudy (braves12):
no
OpenStudy (3mar):
Ok
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OpenStudy (3mar):
Let's start here
OpenStudy (3mar):
you know that
g(x)=x+1
h(x)=x^2+4
ok?
OpenStudy (3mar):
Faster respond please!
OpenStudy (braves12):
yes
OpenStudy (3mar):
what if told you: find g(3) and h(4) for me
Can you share your work?
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OpenStudy (braves12):
i cant do that]
OpenStudy (3mar):
Where are you stuck?
OpenStudy (braves12):
all of it
OpenStudy (3mar):
For g(3): means replace every x in g(x) and put 3 instead!
OpenStudy (braves12):
WHAT
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OpenStudy (3mar):
g(x) is a function of x
we need to calculate this function at a certain point of its variable x
so we want to determine g(x) at 3
Simple now?
OpenStudy (braves12):
kind of
OpenStudy (3mar):
Great!
Happy for that!
I need it 100%
OpenStudy (braves12):
yep
OpenStudy (3mar):
So, depend on your understanding can you believe that?\[g(3)=(3)+1=4\]
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OpenStudy (braves12):
yes
OpenStudy (3mar):
Congratulations!
OpenStudy (3mar):
The same thing for h(x) ........ we need h(4)
\[h(4)=(4)^2+4=16+4=20\]
any problem???
OpenStudy (braves12):
nope
OpenStudy (3mar):
nope=don't understand?
or
nope=no problem?
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OpenStudy (braves12):
no problem
OpenStudy (3mar):
Great!
So we will do the same game for h(g(x))
instead we remove x in h(x) and put a NUMBER (3 OR 5 OR -1), we will remove it and put a FUNCTION [this function is g(x)]!
OpenStudy (braves12):
do what
OpenStudy (3mar):
are you asleep?
OpenStudy (braves12):
yea
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OpenStudy (3mar):
yea about what?
I was waiting and this is not a good evaluation for who are helping you!
OpenStudy (braves12):
that i was asleep
OpenStudy (3mar):
so another time!
OpenStudy (braves12):
ok
OpenStudy (3mar):
Salam!
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OpenStudy (braves12):
what
OpenStudy (3mar):
Salam is our greetings, we are Muslims!
Peace be upon you!