help please Segment BDSegment BD is a perpendicular bisector of segment ACsegment AC . AB=9xAB=9x and CB=5x+16CB=5x+16 . What is the length of CB¯¯¯¯¯CB¯ ? Enter your answer in the box. https://static.k12.com/nextgen_media/assets/8074850-NG_GMT_F_03_U03_Quiz_NP024_109_prompt.jpg
did you get anywhere with it yet?
nope i wasnt there when they taught the lesson
The perpendicular bisector BD - is at right angle to AC and splits AC into 2 equal parts, so AD = DC |dw:1476803948209:dw|
If you look at the two inner triangles, you can say they are congruent from the Side-Angle-Side theorem, Bottom,Right angle, and BD.
that all make sense?
yes im getting it
Corresponding parts of congruent triangles are equal, so the diagonals are the same length AB = BC
They tell you what AB and CB are in the problem, AB=9x and CB=5x+16 |dw:1476804252993:dw|
AB=CB 9x = 5x + 16 4x = 16 x=4 if x is 4, then CB=5*4+16 = 36
so 36 units?
yeah, you understand everything?
yes i get it thank you so much could you check my answers on other problem?
sure
Segment BDSegment BD is a perpendicular bisector of segment ACsegment AC . AD=8x−15AD=8x−15 and DC=57DC=57 . What is the value of x? Enter your answer in the box. for this one i got 9 (same pic)
AD = DC 8x - 15 = 57 yeah x=9, good
Segment BDSegment BD is a perpendicular bisector of segment ACsegment AC , m∠DAB=64°m∠DAB=64° , and m∠DCB=(4x)°m∠DCB=(4x)° . What is the value of x? Enter your answer in the box.
for that one im stuck
Same start, the two inner triangles are congruent. Corresponding sides and angles of congruent triangles are equal. So those two given angles are the same |dw:1476804812222:dw|
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