Question

The springs BA and BC each have a stiffness of 500 N/m and an unstretched length of 3 m. Determine the displacement d of the cord from the wall when a force F = 175 N is applied to the cord.

Answer 1

I need the just the idea.
Thanks in advance.

Answer 2

The horizontal components of the two spring's forces must add up to 175N. So each springs horiz component must be 175/2.

Answer 3

Thank you. Yes I know that.
Then how can we evaluate the tension force in each rope and the orientation angle?

Answer 4

You should be able to use a couple of relations

Answer 5

From the pics:\[\large d^2 + 3^2 = (3+x)^2\]\[\large \cos \theta = \frac{ 3 }{ 3+x }\]\[\large \sin \theta = \frac{ d }{3+x }\]\[\large 500 x \sin \theta =175/2\]

Answer 6

You could also use \(\large \tan \theta = \frac{ d }{ 3 }\) but the above should be enough.

Answer 7

Using the two sin theta equations, and the top equation, you can solve: http://www.wolframalpha.com/input/?i=500x+*+%5Cfrac%7B+d+%7D%7B3%2Bx+%7D%3D175%2F2,+d%5E2+%2B+3%5E2+%3D+(3%2Bx)%5E2

Answer 8

sorry @agent0smith
I did not got theses



where did you get them?
I want the solution of resolving forces to their components, then sum F_x and sum F_y, have two equations, solve them together, and find out the two unknowns. Something like that.

understand me? this is what I am familiar with.