Question

Help me please!!

Answer 1

I am having trouble figuring out what i did wrong, can someone look over my problem?

Answer 2

Here is the question, with the big fat red X

Answer 3

Here is my messy work D:

Answer 4

@zepdrix @IrishBoy123

Answer 5

You missed a sign somewhere...
c2 is supposed to be e^{-6} without the 11.
6-5 = 1.
6+5 = 11.

You should've had a -5 somewhere in there.

Answer 6

How did you cancel it?

Answer 7

Elimination, if you look at the line underneath it.

Answer 8

Your notes are a little too messy to follow :( sorry hmm

Answer 9

Too squished together >.<
You're allowed to skip lines... you know that right? :D lol

Answer 10

Sorry sorry. Ill rewrite it. I was rushing. haha

Answer 11

Kay, what can i do from here?

Answer 12

How bout the other initial data?
Gives us this equation, right?\[\large\rm 0=c_1e^{-5}+c_2e^6\]
Oh oh I see what happened.
You plugged in the first piece of initial data, backwards.

Answer 13

You plugged in (0,1) instead of (1,0)

Answer 14

Oh wow, i didnt do that the first time xD

Answer 15

True :D lol

Answer 16

Oh i think i can use substitution :3

Answer 17

Anyway, you get this,\[\large\rm 0=c_1e^{-5}+c_2e^6\]Multiply this equation by 5,\[\large\rm 0=5c_1e^{-5}+5c_2e^6\]
Oh my.. I think I made a mistake on my paper :O
I think your 11 is correct.. wait wait I checking..

Answer 18

Okie

Answer 19

Ya, I accidentally subtracted that equation from the other one.
I was supposed to add them together.
So you get 11c2e^(stuff)

Ooo boy.. Now I'm not quite sure what went wrong >.<
I gotta rethink this.

Answer 20

Well here is my new "wrong" work. Can you check this?

Answer 21

What did you get for c1 ?
I'm coming up with \(\large\rm -\frac1{11}e^{5}\)

Answer 22

Mmm ya that looks better.

Answer 23

c2 is positive I think... checking...

Answer 24

Yea, it was positive.... I wonder why I didnt get a positive... Hm.