Question

Help please

Answer 1

@Will.H

Answer 2

The equation is of the form
\[
(y+3)^2=b+m x\]
You have two information to find m and b
Do it

Answer 3

Would m and b be the points?

Answer 4

Numbers

Answer 5

I understand but the points that are provided right?

Answer 6

The point (3,-3) is on the parabola. Replace y by -3 and x by 3 to find an equation between m and b

Answer 7

Do the same for the point (0,-2), you get another eqaution. Sole the two equations and you and done

Answer 8

You get
\[
0 = 3 m + b \\ (-2 + 3)^2 = +b
\]
Find m and b

Answer 9

The easy one is b. How much is b?

Answer 10

Are you with me?

Answer 11

Yes i am here just thinking

Answer 12

So would it be (-3-3)^2=b+m(3)

Answer 13

@eliesaab

Answer 14

The second equation
\[
0 = 3 m + b \\ (-2 + 3)^2 = +b\]
gives b=1, replace b by 1 in the first equation to find m

Answer 15

0=3+b

Answer 16

0= 3m +1

Answer 17

You get
\[
m=-\frac 13\]

Answer 18

The final answer is
\[
(y+3)^2=1-\frac{x}{3}
\]

Answer 19

So that is the equation

Answer 20

Yes