Question

What is the vertex of the parabola given by the equation below?

x=-4(y-3)^2+2

Answer 1

Is it -4?

Answer 2

Hint:
The conventional equation of a parabola in vertex form is:
\(y=a(x-h)^2+k\), where the vertex is at (h,k).
If a is positive, parabola opens upwards.
However, we can turn the parabola 90 degrees, i.e. let the parabola sit sideways, opens left/right, by exchanging x and y to give
\(x=a(y-k)^2+h\), which makes the vertex at again (h,k).
if a is positive, parabola opens to the right.
by comparing the given equation with the standard forms, the solution can be obtained.

Note: a vertex is defined by an ordered pair, like (4,-2) and not a single number.

Answer 3

(3,-2)?

Answer 4

Did you follow mathmate's post? the vertex is an (x,y) point.
it is (h,k)
where h and k match up with
x= a (y − k)^2+h
x=-4 (y - 3)^2+2

what number matches up with "h" ?
and what number matches up with k ?

Answer 5

With h 2 and with k -3

Answer 6

yes, h is 2
but