Question

How many moles of OH- are in 200.0 mL of a 1.25 M NaOH solution?

Answer 1

is it .25mol

Answer 2

you would need to use the molarity formula,

\(\sf Molarity=\dfrac{moles}{L_{solution}}\)

Therefore, \(\sf moles=Molarity*L_{solution}=(1.25 ~mol/L)*(0.2 ~L)\)

Answer 3

Btw, this is true because each molecule of NaOH has one \(OH^-\) ion.

If the compound produced a different amount, e.g. \(Ca(OH)_2\), the answer would be different.