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How many moles of OH- are in 200.0 mL of a 1.25 M NaOH solution?
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is it .25mol
you would need to use the molarity formula, \(\sf Molarity=\dfrac{moles}{L_{solution}}\) Therefore, \(\sf moles=Molarity*L_{solution}=(1.25 ~mol/L)*(0.2 ~L)\)
Btw, this is true because each molecule of NaOH has one \(OH^-\) ion. If the compound produced a different amount, e.g. \(Ca(OH)_2\), the answer would be different.
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