A 15 kg curling rock is released with a speed of 2.02 m/s and slides to a stop in 11 meters. What force of friction acts on the rock?

Question

diglet · Answer

Ok,I'll give it a shot. Firstly we need to calculate time taken to stop. |dw:1477447214237:dw|

diglet · Answer

The we use this time to calculate the acceleration using v = u + at.

a = (v-u)  /  t

a = (0 - 2.02) /  10.89
a = -0.185 ms^-2

diglet · Answer

The force that causes and acceleration is given by the formula f=ma,

f is the friction force in this case.

f = 15kg / (-) 0.18549...
f= (-)80.9 N

This force is positive or negative depending on which way you look at it.

Hope this is correct and that it helps

irishboy123 · Answer

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