WILL FAN AND MEDAL If ice forms for 0≤t≤30≤t≤3, at what time in this interval is the ice thickest? At what time is the ice forming fastest? Ice is thickest at t= Ice is forming fastest at t=
"0≤t≤30≤t≤3" That doesn't make sense.
i meant 0≤t≤3
oh, i'm sorry i forgot to include that, At time t, in hours, a lake is covered with ice of thickness y cm, where y=0.3t^1.7
Find the derivative, set it equal to zero to find the maximum thickness. Find the second derivative, set equal to zero, to find when it's forming fastest.
so the derivative is .51t^.7
.51t^0.7 = 0
there are no solution
It is true when t = 0 Then, once you have that value, don't forget to check the endpoint as well, t=3, by plugging into the original function. You want the largest value.
so when t = 0, the solution is 0 when t=3, the solution is .84 ???
so then thickest at .84 and growing fastest at that point as well?
Not thickest AT 0.84. t is a time value. y is the thickness value. Make sure you know what you are finding. For growing fastest you need second derivative... but i'm pretty sure it'll be fastest at t=3 as well.
so the second derivative is .36^-.3
Looks about right. And that'll never equal zero.
so increasing fastest is at t= 3 hours!
Yep, a graph would confirm both https://www.google.com/search?q=0.3t%5E1.7&rlz=1C1AOHY_enUS708US708&oq=0.3t%5E1.7&aqs=chrome..69i57&sourceid=chrome&ie=UTF-8 Kind of a very simple function to give for a question like this...
so i want the y value at x=.84
What...? You should know which value is which... At t=3, what is the thickness y? It's not .84 btw.
oh wait i got confused XD the x value of 3 is where it is increasing fastest and y in the thickness
how do i get an exact value? i get something close to 2
Just don't simplify?
oh i got it, 1.942 (3,1.942)
wait, but it says t is thickest at a certain point. so it is thickest at t = 3 hours
i understand now XD
Looks right.
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