Question

Hard chem question please help!! :)

Answer 1

this is it!

Answer 2

I gotchuuuu gimme a minute

Answer 3

\[.0256L\cdot(.188MCuSO_4) = .00481\text{moles of copper(II)sulfate} \\ \text{since the molar ratio is 1 \to 1 then there's also .00481moles of sodium carbonate}\]
\[\text{then taking the moles and dividing \it by the molarity}\\\text{ of sodium carbonate we get the liters of sodium sulfate required}\]
Then multiply by 1000 to get the ml of sodium carbonate required. again becuase of the 1 to 1molar ratio just convert the .00481 moles to grams of copper (ii)carbonate

Answer 4

Okay thank you so much! That makes sense. How do you do part b?

Answer 5

Try using the same method FosterWestLake used, but substitute for different values, @KarisLeft