Question

@mayankdevnani

Answer 1

If each edge of a cube is increasing at the constant rate of 3 cm/s, how fast is the volume of the cube increasing when the length x of an edge is 10 cm long?

Answer 2

I know volume for the cube is l*w*h, but I'm not sure what to do with that or any of the info given... this lesson completely confused me in class

Answer 3

Let the length of edge of cube be x cm
So,volume of cube=x^3
Derivative = 3x^2 dx/dt
plug x=10cm and dx/dt=3cm/s

Answer 4

hey lwh is volume of cuboid

Answer 5

for cube,each edge is equal

Answer 6

take your time and let me know where you find your difficulty :)

Answer 7

So taking the derivative has to be with respect to t?

Answer 8

yea cuz it is increasing with time

Answer 9

we relate it with TIME

Answer 10

I think it needs to be a little more clear

V = x^3


take the derivative with respect to time
dV/dt = 3x dx/dt

and then you plug in what you know and you're solving for dV/dt