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Mathematics 16 Online
OpenStudy (iwanttogotostanford):

NEED HELP WITH THESE 2 ASAP:

OpenStudy (steve816):

Ok sure.

OpenStudy (iwanttogotostanford):

@3mar please help ASAP :-)

OpenStudy (iwanttogotostanford):

@welshfella

OpenStudy (3mar):

Hello!

OpenStudy (3mar):

How could I help you?

OpenStudy (iwanttogotostanford):

what would be the solutions to the first and second one please??

OpenStudy (iwanttogotostanford):

@3mar

OpenStudy (iwanttogotostanford):

@3mar

OpenStudy (iwanttogotostanford):

@3mar please just share the answer I will work backwards from there

OpenStudy (3mar):

Well, I am here.

OpenStudy (3mar):

https://www.desmos.com/calculator/3joqbw3xu2 Take a look at this. The domain and range are clear here! This is for the first question.

OpenStudy (triciaal):

this was a little tricky the range is the set of output values that satisfy the function from lowest to highest when x is negative the square is positive and you can subtract 2 when x is -1 then y = -2 when x = 0 y = -1 when x is positive then y is positive so the lowest is -2

OpenStudy (iwanttogotostanford):

@triciaal so for #2 it would be B" correct because y is greater than or equal to -2?

OpenStudy (triciaal):

@3mar you input -1 in the equation instead of -2 @iwanttogotostanford see the graph but minimum at -2

OpenStudy (triciaal):

correct

OpenStudy (3mar):

Sorry

OpenStudy (triciaal):

@3mar it's ok correct process

OpenStudy (3mar):

Thank you for good explanation.

OpenStudy (iwanttogotostanford):

@3mar

OpenStudy (3mar):

One question per one post, please.

OpenStudy (triciaal):

you never want zero in the denominator and you don't want to take the square root of a negative yes try to limit the number of questions per post

OpenStudy (3mar):

Can we start in new post, please?

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